行业知识
【【C语言简单小题学习-1】】
2026-11-08 11:39:52
来源:互联网转载
实现九九乘法表
// �index.php/tags-41973.html" >��出乘法口诀表 int main(){ int i = 0; int j = 0; for (i = 1; i for (j = 1; j int input = 0; srand((unsigned int)time(NULL)); do { menu(); printf("请选择:"); scanf("%d", &input); switch(input) { case 1: game(); break; case 0 : printf("退出游戏\n"); break; default : printf("输入错误\n"); break; } } while (input); return 0;}void menu(){ printf("**************************\n"); printf("**************************\n"); printf("*****请开始你的选择*******\n"); printf(" 1.begin 0.end \n"); printf("**************************\n"); printf("**************************\n"); printf("**************************\n"); printf("**************************\n");}void game(){ int a = 0; int b = 0; a = rand() % 100 + 1; // 取1到100以内的数字 while (1) { printf("请输入您想要输入的数字:\n"); scanf("%d", &b); if (b 素数判断
// 素数判断#define _CRT_SECURE_NO_WARNINGS 1#include#include#include//素数判断int panduan(int input);int main(){ int input = 0; printf("请输入想要的数字:\n"); scanf("%d", &input); // 得到输入input int a = panduan(input); if (a == 0) { printf("不是 素数\n"); } else { printf("是 素数 !"); } return 0;}int panduan(int input){ int i = 0; for (i = 2; i 有序数组的查找
// 有序数组的查找#define _CRT_SECURE_NO_WARNINGS 1#include#include#include// 有序数组的查找int chaozhao(int arr[], int n, int sz);int main(){ int n = 0; int arr[] = { 1,2,3,4,5,6,7,8,9,10,11 }; int sz = sizeof(arr) / sizeof(arr[0]); printf("请输入数字:\n"); scanf("%d", &n); int b= chazhao( arr, n, sz); if (b == 0) { printf("没找到"); } else { printf("找到了并且下标是%d\n", b); } return 0;}int chazhao(int arr[], int n, int sz){ int left = 0; int right = sz - 1; while (left int mid = (left + right) / 2; if (n arr[mid]) { left = mid + 1; } else if (n 有序打印数字既递归的学习
#define _CRT_SECURE_NO_WARNINGS 1#include#include#include// 递归的简易设计// void digui(int a);int main(){ int input = 0; printf("请输入想要输入的数字\n"); scanf("%d", &input); digui(input); return 0;}void digui(int n){ if (n > 9) { digui(n / 10); } printf("%d ", n%10);}
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